1) for in

主要用来遍历对象

let father = {name:'张三', age:18, study:function(){}};

for(const n in father) {
    console.log(n);
}
for(const n in son) {
    console.log(n, son[n]);
}

2) for of

主要用来遍历数组,也可以是其它可迭代对象,如 Map,Set 等

let a1 = [1,2,3];

for(const i of a1) {
    console.log(i);
}

let a2 = [
    {name:'张三', age:18},
    {name:'李四', age:20},
    {name:'王五', age:22}
];

for(const obj of a2) {
    console.log(obj.name, obj.age);
}

for(const {name,age} of a2) {
    console.log(name, age);
}

3) try catch